diff --git a/solution/2000-2099/2033.Minimum Operations to Make a Uni-Value Grid/README.md b/solution/2000-2099/2033.Minimum Operations to Make a Uni-Value Grid/README.md
index 8b89ac1c47017..6b6c3c932be5a 100644
--- a/solution/2000-2099/2033.Minimum Operations to Make a Uni-Value Grid/README.md
+++ b/solution/2000-2099/2033.Minimum Operations to Make a Uni-Value Grid/README.md
@@ -194,6 +194,44 @@ func abs(x int) int {
}
```
+#### TypeScript
+
+```ts
+function minOperations(grid: number[][], x: number): number {
+ const arr = grid.flat(2);
+ arr.sort((a, b) => a - b);
+ const median = arr[Math.floor(arr.length / 2)];
+
+ let res = 0;
+ for (const val of arr) {
+ const c = Math.abs(val - median) / x;
+ if (c !== (c | 0)) return -1;
+ res += c;
+ }
+
+ return res;
+}
+```
+
+#### JavaScript
+
+```js
+function minOperations(grid, x) {
+ const arr = grid.flat(2);
+ arr.sort((a, b) => a - b);
+ const median = arr[Math.floor(arr.length / 2)];
+
+ let res = 0;
+ for (const val of arr) {
+ const c = Math.abs(val - median) / x;
+ if (c !== (c | 0)) return -1;
+ res += c;
+ }
+
+ return res;
+}
+```
+
diff --git a/solution/2000-2099/2033.Minimum Operations to Make a Uni-Value Grid/README_EN.md b/solution/2000-2099/2033.Minimum Operations to Make a Uni-Value Grid/README_EN.md
index 202e609bd8de3..557513f032941 100644
--- a/solution/2000-2099/2033.Minimum Operations to Make a Uni-Value Grid/README_EN.md
+++ b/solution/2000-2099/2033.Minimum Operations to Make a Uni-Value Grid/README_EN.md
@@ -186,6 +186,44 @@ func abs(x int) int {
}
```
+#### TypeScript
+
+```ts
+function minOperations(grid: number[][], x: number): number {
+ const arr = grid.flat(2);
+ arr.sort((a, b) => a - b);
+ const median = arr[Math.floor(arr.length / 2)];
+
+ let res = 0;
+ for (const val of arr) {
+ const c = Math.abs(val - median) / x;
+ if (c !== (c | 0)) return -1;
+ res += c;
+ }
+
+ return res;
+}
+```
+
+#### JavaScript
+
+```js
+function minOperations(grid, x) {
+ const arr = grid.flat(2);
+ arr.sort((a, b) => a - b);
+ const median = arr[Math.floor(arr.length / 2)];
+
+ let res = 0;
+ for (const val of arr) {
+ const c = Math.abs(val - median) / x;
+ if (c !== (c | 0)) return -1;
+ res += c;
+ }
+
+ return res;
+}
+```
+
diff --git a/solution/2000-2099/2033.Minimum Operations to Make a Uni-Value Grid/Solution.js b/solution/2000-2099/2033.Minimum Operations to Make a Uni-Value Grid/Solution.js
new file mode 100644
index 0000000000000..43d9b37cd033c
--- /dev/null
+++ b/solution/2000-2099/2033.Minimum Operations to Make a Uni-Value Grid/Solution.js
@@ -0,0 +1,14 @@
+function minOperations(grid, x) {
+ const arr = grid.flat(2);
+ arr.sort((a, b) => a - b);
+ const median = arr[Math.floor(arr.length / 2)];
+
+ let res = 0;
+ for (const val of arr) {
+ const c = Math.abs(val - median) / x;
+ if (c !== (c | 0)) return -1;
+ res += c;
+ }
+
+ return res;
+}
diff --git a/solution/2000-2099/2033.Minimum Operations to Make a Uni-Value Grid/Solution.ts b/solution/2000-2099/2033.Minimum Operations to Make a Uni-Value Grid/Solution.ts
new file mode 100644
index 0000000000000..e470b9bcdb6c9
--- /dev/null
+++ b/solution/2000-2099/2033.Minimum Operations to Make a Uni-Value Grid/Solution.ts
@@ -0,0 +1,14 @@
+function minOperations(grid: number[][], x: number): number {
+ const arr = grid.flat(2);
+ arr.sort((a, b) => a - b);
+ const median = arr[Math.floor(arr.length / 2)];
+
+ let res = 0;
+ for (const val of arr) {
+ const c = Math.abs(val - median) / x;
+ if (c !== (c | 0)) return -1;
+ res += c;
+ }
+
+ return res;
+}
diff --git a/solution/3400-3499/3497.Analyze Subscription Conversion/README.md b/solution/3400-3499/3497.Analyze Subscription Conversion/README.md
new file mode 100644
index 0000000000000..2318cffe94d0c
--- /dev/null
+++ b/solution/3400-3499/3497.Analyze Subscription Conversion/README.md
@@ -0,0 +1,220 @@
+---
+comments: true
+difficulty: 中等
+edit_url: https://github.com/doocs/leetcode/edit/main/solution/3400-3499/3497.Analyze%20Subscription%20Conversion/README.md
+tags:
+ - 数据库
+---
+
+
+
+# [3497. 分析订阅转化](https://leetcode.cn/problems/analyze-subscription-conversion)
+
+[English Version](/solution/3400-3499/3497.Analyze%20Subscription%20Conversion/README_EN.md)
+
+## 题目描述
+
+
+
+表：UserActivity
+
+
++------------------+---------+
+| Column Name | Type |
++------------------+---------+
+| user_id | int |
+| activity_date | date |
+| activity_type | varchar |
+| activity_duration| int |
++------------------+---------+
+(user_id, activity_date, activity_type) 是这张表的唯一主键。
+activity_type 是('free_trial', 'paid', 'cancelled')中的一个。
+activity_duration 是用户当天在平台上花费的分钟数。
+每一行表示一个用户在特定日期的活动。
+
+
+订阅服务想要分析用户行为模式。公司提供7天免费试用，试用结束后，用户可以选择订阅 付费计划 或 取消。编写解决方案：
+
+
+ - 查找从免费试用转为付费订阅的用户
+ - 计算每位用户在 免费试用 期间的 平均每日活动时长（四舍五入至小数点后
2 位）
+ - 计算每位用户在 付费 订阅期间的 平均每日活动时长（四舍五入到小数点后
2 位）
+
+
+返回结果表以 user_id 升序 排序。
+
+结果格式如下所示。
+
+
+
+示例：
+
+
+
输入：
+
+
UserActivity 表：
+
+
++---------+---------------+---------------+-------------------+
+| user_id | activity_date | activity_type | activity_duration |
++---------+---------------+---------------+-------------------+
+| 1 | 2023-01-01 | free_trial | 45 |
+| 1 | 2023-01-02 | free_trial | 30 |
+| 1 | 2023-01-05 | free_trial | 60 |
+| 1 | 2023-01-10 | paid | 75 |
+| 1 | 2023-01-12 | paid | 90 |
+| 1 | 2023-01-15 | paid | 65 |
+| 2 | 2023-02-01 | free_trial | 55 |
+| 2 | 2023-02-03 | free_trial | 25 |
+| 2 | 2023-02-07 | free_trial | 50 |
+| 2 | 2023-02-10 | cancelled | 0 |
+| 3 | 2023-03-05 | free_trial | 70 |
+| 3 | 2023-03-06 | free_trial | 60 |
+| 3 | 2023-03-08 | free_trial | 80 |
+| 3 | 2023-03-12 | paid | 50 |
+| 3 | 2023-03-15 | paid | 55 |
+| 3 | 2023-03-20 | paid | 85 |
+| 4 | 2023-04-01 | free_trial | 40 |
+| 4 | 2023-04-03 | free_trial | 35 |
+| 4 | 2023-04-05 | paid | 45 |
+| 4 | 2023-04-07 | cancelled | 0 |
++---------+---------------+---------------+-------------------+
+
+
+
输出：
+
+
++---------+--------------------+-------------------+
+| user_id | trial_avg_duration | paid_avg_duration |
++---------+--------------------+-------------------+
+| 1 | 45.00 | 76.67 |
+| 3 | 70.00 | 63.33 |
+| 4 | 37.50 | 45.00 |
++---------+--------------------+-------------------+
+
+
+
解释：
+
+
+ - 用户 1:
+
+
+ - 体验了 3 天免费试用，时长分别为 45，30 和 60 分钟。
+ - 平均试用时长：(45 + 30 + 60) / 3 = 45.00 分钟。
+ - 拥有 3 天付费订阅，时长分别为 75，90 和 65分钟。
+ - 平均花费市场：(75 + 90 + 65) / 3 = 76.67 分钟。
+
+
+ - 用户 2:
+
+ - 体验了 3 天免费试用，时长分别为 55，25 和 50 分钟。
+ - 平均试用时长：(55 + 25 + 50) / 3 = 43.33 分钟。
+ - 没有转为付费订阅（只有 free_trial 和 cancelled 活动）。
+ - 未包含在输出中，因为他未转换为付费用户。
+
+
+ - 用户 3:
+
+ - 体验了 3 天免费试用，时长分别为 70，60 和 80 分钟。
+ - 平均试用时长：(70 + 60 + 80) / 3 = 70.00 分钟。
+ - 拥有 3 天付费订阅，时长分别为 50，55 和 85 分钟。
+ - 平均花费时长：(50 + 55 + 85) / 3 = 63.33 分钟。
+
+
+ - 用户 4:
+
+ - 体验了 2 天免费试用，时长分别为 40 和 35 分钟。
+ - 平均试用时长：(40 + 35) / 2 = 37.50 分钟。
+ - 在取消前有 1 天的付费订阅，时长为45分钟。
+ - 平均花费时长：45.00 分钟。
+
+
+
+
+
+
结果表仅包括从免费试用转为付费订阅的用户（用户 1，3 和 4），并且以 user_id 升序排序。
+
Table: UserActivity
+
+
++------------------+---------+
+| Column Name | Type |
++------------------+---------+
+| user_id | int |
+| activity_date | date |
+| activity_type | varchar |
+| activity_duration| int |
++------------------+---------+
+(user_id, activity_date, activity_type) is the unique key for this table.
+activity_type is one of ('free_trial', 'paid', 'cancelled').
+activity_duration is the number of minutes the user spent on the platform that day.
+Each row represents a user's activity on a specific date.
+
+
+A subscription service wants to analyze user behavior patterns. The company offers a 7-day free trial, after which users can subscribe to a paid plan or cancel. Write a solution to:
+
+
+ - Find users who converted from free trial to paid subscription
+ - Calculate each user's average daily activity duration during their free trial period (rounded to
2 decimal places)
+ - Calculate each user's average daily activity duration during their paid subscription period (rounded to
2 decimal places)
+
+
+Return the result table ordered by user_id in ascending order.
+
+The result format is in the following example.
+
+
+Example:
+
+
+
Input:
+
+
UserActivity table:
+
+
++---------+---------------+---------------+-------------------+
+| user_id | activity_date | activity_type | activity_duration |
++---------+---------------+---------------+-------------------+
+| 1 | 2023-01-01 | free_trial | 45 |
+| 1 | 2023-01-02 | free_trial | 30 |
+| 1 | 2023-01-05 | free_trial | 60 |
+| 1 | 2023-01-10 | paid | 75 |
+| 1 | 2023-01-12 | paid | 90 |
+| 1 | 2023-01-15 | paid | 65 |
+| 2 | 2023-02-01 | free_trial | 55 |
+| 2 | 2023-02-03 | free_trial | 25 |
+| 2 | 2023-02-07 | free_trial | 50 |
+| 2 | 2023-02-10 | cancelled | 0 |
+| 3 | 2023-03-05 | free_trial | 70 |
+| 3 | 2023-03-06 | free_trial | 60 |
+| 3 | 2023-03-08 | free_trial | 80 |
+| 3 | 2023-03-12 | paid | 50 |
+| 3 | 2023-03-15 | paid | 55 |
+| 3 | 2023-03-20 | paid | 85 |
+| 4 | 2023-04-01 | free_trial | 40 |
+| 4 | 2023-04-03 | free_trial | 35 |
+| 4 | 2023-04-05 | paid | 45 |
+| 4 | 2023-04-07 | cancelled | 0 |
++---------+---------------+---------------+-------------------+
+
+
+
Output:
+
+
++---------+--------------------+-------------------+
+| user_id | trial_avg_duration | paid_avg_duration |
++---------+--------------------+-------------------+
+| 1 | 45.00 | 76.67 |
+| 3 | 70.00 | 63.33 |
+| 4 | 37.50 | 45.00 |
++---------+--------------------+-------------------+
+
+
+
Explanation:
+
+
+ - User 1:
+
+
+ - Had 3 days of free trial with durations of 45, 30, and 60 minutes.
+ - Average trial duration: (45 + 30 + 60) / 3 = 45.00 minutes.
+ - Had 3 days of paid subscription with durations of 75, 90, and 65 minutes.
+ - Average paid duration: (75 + 90 + 65) / 3 = 76.67 minutes.
+
+
+ - User 2:
+
+ - Had 3 days of free trial with durations of 55, 25, and 50 minutes.
+ - Average trial duration: (55 + 25 + 50) / 3 = 43.33 minutes.
+ - Did not convert to a paid subscription (only had free_trial and cancelled activities).
+ - Not included in the output because they didn't convert to paid.
+
+
+ - User 3:
+
+ - Had 3 days of free trial with durations of 70, 60, and 80 minutes.
+ - Average trial duration: (70 + 60 + 80) / 3 = 70.00 minutes.
+ - Had 3 days of paid subscription with durations of 50, 55, and 85 minutes.
+ - Average paid duration: (50 + 55 + 85) / 3 = 63.33 minutes.
+
+
+ - User 4:
+
+ - Had 2 days of free trial with durations of 40 and 35 minutes.
+ - Average trial duration: (40 + 35) / 2 = 37.50 minutes.
+ - Had 1 day of paid subscription with duration of 45 minutes before cancelling.
+ - Average paid duration: 45.00 minutes.
+
+
+
+
+
+
The result table only includes users who converted from free trial to paid subscription (users 1, 3, and 4), and is ordered by user_id in ascending order.
+