feat: add solutions to weekly contest 412 (doocs#3450)

Author: yanglbme

solution/0600-0699/0626.Exchange Seats/README_EN.md

@@ -27,7 +27,7 @@ tags:
 +-------------+---------+
 id is the primary key (unique value) column for this table.
 Each row of this table indicates the name and the ID of a student.
-id is a continuous increment.
+The ID sequence always starts from 1 and increments continuously.
 </pre>
 
 <p>&nbsp;</p>

solution/0600-0699/0690.Employee Importance/README.md

@@ -172,6 +172,8 @@ public:
 };
 ```
 
+#### Go
+
 ```go
 /**
  * Definition for Employee.

solution/0600-0699/0690.Employee Importance/README_EN.md

@@ -165,6 +165,8 @@ public:
 };
 ```
 
+#### Go
+
 ```go
 /**
  * Definition for Employee.

solution/1000-1099/1052.Grumpy Bookstore Owner/README_EN.md

@@ -19,32 +19,38 @@ tags:
 
 <!-- description:start -->
 
-<p>There is a bookstore owner that has a store open for <code>n</code> minutes. Every minute, some number of customers enter the store. You are given an integer array <code>customers</code> of length <code>n</code> where <code>customers[i]</code> is the number of the customer that enters the store at the start of the <code>i<sup>th</sup></code> minute and all those customers leave after the end of that minute.</p>
+<p>There is a bookstore owner that has a store open for <code>n</code> minutes. You are given an integer array <code>customers</code> of length <code>n</code> where <code>customers[i]</code> is the number of the customers that enter the store at the start of the <code>i<sup>th</sup></code> minute and all those customers leave after the end of that minute.</p>
 
-<p>On some minutes, the bookstore owner is grumpy. You are given a binary array grumpy where <code>grumpy[i]</code> is <code>1</code> if the bookstore owner is grumpy during the <code>i<sup>th</sup></code> minute, and is <code>0</code> otherwise.</p>
+<p>During certain minutes, the bookstore owner is grumpy. You are given a binary array grumpy where <code>grumpy[i]</code> is <code>1</code> if the bookstore owner is grumpy during the <code>i<sup>th</sup></code> minute, and is <code>0</code> otherwise.</p>
 
-<p>When the bookstore owner is grumpy, the customers of that minute are not satisfied, otherwise, they are satisfied.</p>
+<p>When the bookstore owner is grumpy, the customers entering during that minute are not <strong>satisfied</strong>. Otherwise, they are satisfied.</p>
 
-<p>The bookstore owner knows a secret technique to keep themselves not grumpy for <code>minutes</code> consecutive minutes, but can only use it once.</p>
+<p>The bookstore owner knows a secret technique to remain <strong>not grumpy</strong> for <code>minutes</code> consecutive minutes, but this technique can only be used <strong>once</strong>.</p>
 
-<p>Return <em>the maximum number of customers that can be satisfied throughout the day</em>.</p>
+<p>Return the <strong>maximum</strong> number of customers that can be <em>satisfied</em> throughout the day.</p>
 
 <p>&nbsp;</p>
 <p><strong class="example">Example 1:</strong></p>
 
-<pre>
-<strong>Input:</strong> customers = [1,0,1,2,1,1,7,5], grumpy = [0,1,0,1,0,1,0,1], minutes = 3
-<strong>Output:</strong> 16
-<strong>Explanation:</strong> The bookstore owner keeps themselves not grumpy for the last 3 minutes. 
-The maximum number of customers that can be satisfied = 1 + 1 + 1 + 1 + 7 + 5 = 16.
-</pre>
+<div class="example-block">
+<p><strong>Input:</strong> <span class="example-io">customers = [1,0,1,2,1,1,7,5], grumpy = [0,1,0,1,0,1,0,1], minutes = 3</span></p>
+
+<p><strong>Output:</strong> <span class="example-io">16</span></p>
+
+<p><strong>Explanation:</strong></p>
+
+<p>The bookstore owner keeps themselves not grumpy for the last 3 minutes.</p>
+
+<p>The maximum number of customers that can be satisfied = 1 + 1 + 1 + 1 + 7 + 5 = 16.</p>
+</div>
 
 <p><strong class="example">Example 2:</strong></p>
 
-<pre>
-<strong>Input:</strong> customers = [1], grumpy = [0], minutes = 1
-<strong>Output:</strong> 1
-</pre>
+<div class="example-block">
+<p><strong>Input:</strong> <span class="example-io">customers = [1], grumpy = [0], minutes = 1</span></p>
+
+<p><strong>Output:</strong> <span class="example-io">1</span></p>
+</div>
 
 <p>&nbsp;</p>
 <p><strong>Constraints:</strong></p>

solution/1100-1199/1152.Analyze User Website Visit Pattern/README_EN.md

@@ -36,7 +36,9 @@ tags:
 	<li>Also, if the pattern is <code>[&quot;luffy&quot;, &quot;luffy&quot;, &quot;luffy&quot;]</code>, the score is the number of users <code>x</code> such that <code>x</code> visited <code>&quot;luffy&quot;</code> three different times at different timestamps.</li>
 </ul>
 
-<p>Return <em>the <strong>pattern</strong> with the largest <strong>score</strong></em>. If there is more than one pattern with the same largest score, return the lexicographically smallest such pattern.</p>
+<p>Return the <strong>pattern</strong> with the largest <strong>score</strong>. If there is more than one pattern with the same largest score, return the lexicographically smallest such pattern.</p>
+
+<p>Note that the websites in a pattern <strong>do not</strong> need to be visited <em>contiguously</em>, they only need to be visited in the order they appeared in the pattern.</p>
 
 <p>&nbsp;</p>
 <p><strong class="example">Example 1:</strong></p>

solution/1300-1399/1334.Find the City With the Smallest Number of Neighbors at a Threshold Distance/README_EN.md

@@ -28,7 +28,9 @@ tags:
 
 <p>&nbsp;</p>
 <p><strong class="example">Example 1:</strong></p>
-<img alt="" src="https://fastly.jsdelivr.net/gh/doocs/leetcode@main/solution/1300-1399/1334.Find%20the%20City%20With%20the%20Smallest%20Number%20of%20Neighbors%20at%20a%20Threshold%20Distance/images/find_the_city_01.png" style="width: 300px; height: 225px;" />
+
+<p><img alt="" src="https://fastly.jsdelivr.net/gh/doocs/leetcode@main/solution/1300-1399/1334.Find%20the%20City%20With%20the%20Smallest%20Number%20of%20Neighbors%20at%20a%20Threshold%20Distance/images/problem1334example1.png" style="width: 300px; height: 224px;" /></p>
+
 <pre>
 <strong>Input:</strong> n = 4, edges = [[0,1,3],[1,2,1],[1,3,4],[2,3,1]], distanceThreshold = 4
 <strong>Output:</strong> 3
@@ -42,7 +44,9 @@ Cities 0 and 3 have 2 neighboring cities at a distanceThreshold = 4, but we have
 </pre>
 
 <p><strong class="example">Example 2:</strong></p>
-<img alt="" src="https://fastly.jsdelivr.net/gh/doocs/leetcode@main/solution/1300-1399/1334.Find%20the%20City%20With%20the%20Smallest%20Number%20of%20Neighbors%20at%20a%20Threshold%20Distance/images/find_the_city_02.png" style="width: 300px; height: 225px;" />
+
+<p><img alt="" src="https://fastly.jsdelivr.net/gh/doocs/leetcode@main/solution/1300-1399/1334.Find%20the%20City%20With%20the%20Smallest%20Number%20of%20Neighbors%20at%20a%20Threshold%20Distance/images/problem1334example0.png" style="width: 300px; height: 224px;" /></p>
+
 <pre>
 <strong>Input:</strong> n = 5, edges = [[0,1,2],[0,4,8],[1,2,3],[1,4,2],[2,3,1],[3,4,1]], distanceThreshold = 2
 <strong>Output:</strong> 0

solution/1300-1399/1334.Find the City With the Smallest Number of Neighbors at a Threshold Distance/images/problem1334example0.png

@@ -41,10 +41,9 @@ title is the name of the movie.
 | name          | varchar |
 +---------------+---------+
 user_id is the primary key (column with unique values) for this table.
+The column 'name' has unique values.
 </pre>
 
-<p>&nbsp;</p>
-
 <p>Table: <code>MovieRating</code></p>
 
 <pre>
@@ -56,7 +55,7 @@ user_id is the primary key (column with unique values) for this table.
 | rating        | int     |
 | created_at    | date    |
 +---------------+---------+
-(movie_id, user_id) is the primary key (column with unique values)&nbsp;for this table.
+(movie_id, user_id) is the primary key (column with unique values) for this table.
 This table contains the rating of a movie by a user in their review.
 created_at is the user&#39;s review date. 
 </pre>

solution/1300-1399/1334.Find the City With the Smallest Number of Neighbors at a Threshold Distance/images/problem1334example1.png

@@ -65,12 +65,12 @@ Course 0 is not a prerequisite of course 1, but the opposite is true.
 	<li><code>2 &lt;= numCourses &lt;= 100</code></li>
 	<li><code>0 &lt;= prerequisites.length &lt;= (numCourses * (numCourses - 1) / 2)</code></li>
 	<li><code>prerequisites[i].length == 2</code></li>
-	<li><code>0 &lt;= a<sub>i</sub>, b<sub>i</sub> &lt;= n - 1</code></li>
+	<li><code>0 &lt;= a<sub>i</sub>, b<sub>i</sub> &lt;= numCourses - 1</code></li>
 	<li><code>a<sub>i</sub> != b<sub>i</sub></code></li>
 	<li>All the pairs <code>[a<sub>i</sub>, b<sub>i</sub>]</code> are <strong>unique</strong>.</li>
 	<li>The prerequisites graph has no cycles.</li>
 	<li><code>1 &lt;= queries.length &lt;= 10<sup>4</sup></code></li>
-	<li><code>0 &lt;= u<sub>i</sub>, v<sub>i</sub> &lt;= n - 1</code></li>
+	<li><code>0 &lt;= u<sub>i</sub>, v<sub>i</sub> &lt;= numCourses - 1</code></li>
 	<li><code>u<sub>i</sub> != v<sub>i</sub></code></li>
 </ul>