feat: add sql solution to lc problem: No.0603 (doocs#750)

No.0603.Consecutive Available Seats

Co-authored-by: John Law <johnlaw.po@gmail.com>

Author: Dhoni77

solution/0600-0699/0603.Consecutive Available Seats/README.md

@@ -62,7 +62,14 @@ Cinema 表:
 ### **SQL**
 
 ```sql
-
+SELECT c1.seat_id
+FROM   Cinema c1,
+       Cinema c2
+WHERE  ( ( c1.seat_id = c2.seat_id + 1 )
+          OR ( c1.seat_id = c2.seat_id - 1 ) )
+       AND ( c1.free = 1
+             AND c2.free = 1 )
+GROUP BY seat_id; 
 ```
 
 <!-- tabs:end -->

solution/0600-0699/0603.Consecutive Available Seats/README_EN.md

@@ -59,7 +59,14 @@ Cinema table:
 ### **SQL**
 
 ```sql
-
+SELECT c1.seat_id
+FROM   Cinema c1,
+       Cinema c2
+WHERE  ( ( c1.seat_id = c2.seat_id + 1 )
+          OR ( c1.seat_id = c2.seat_id - 1 ) )
+       AND ( c1.free = 1
+             AND c2.free = 1 )
+GROUP BY seat_id; 
 ```
 
 <!-- tabs:end -->

solution/0600-0699/0603.Consecutive Available Seats/Solution.sql

@@ -0,0 +1,8 @@
+SELECT c1.seat_id
+FROM   Cinema c1,
+       Cinema c2
+WHERE  ( ( c1.seat_id = c2.seat_id + 1 )
+          OR ( c1.seat_id = c2.seat_id - 1 ) )
+       AND ( c1.free = 1
+             AND c2.free = 1 )
+GROUP BY seat_id;