feat: add sql solution to lc problem: No.1270 (doocs#745)

No.1270. All People Report to the Given Manager

Author: Dhoni77

solution/1200-1299/1270.All People Report to the Given Manager/README.md

@@ -67,12 +67,22 @@ employee_id 是 3, 8 ，9 的职员不会直接或间接的汇报给公司 CEO
 
 <!-- 这里可写通用的实现逻辑 -->
 
+
 <!-- tabs:start -->
 
 ### **SQL**
 
 ```sql
-
+# Write your MySQL query statement below
+
+SELECT e1.employee_id
+FROM   employees e1
+JOIN   employees e2
+JOIN   employees e3
+ON     e1.manager_id=e2.employee_id
+AND    e2.manager_id=e3.employee_id
+where  e3.manager_id=1
+AND    e1.employee_id!=1;
 ```
 
 <!-- tabs:end -->

solution/1200-1299/1270.All People Report to the Given Manager/README_EN.md

@@ -64,14 +64,23 @@ The employee with employee_id 7 reports their work indirectly to the head of the
 The employees with employee_id 3, 8, and 9 do not report their work to the head of the company directly or indirectly. 
 </pre>
 
-## Solutions
+## Solution
 
 <!-- tabs:start -->
 
 ### **SQL**
 
 ```sql
-
+# Write your MySQL query statement below
+
+SELECT e1.employee_id
+FROM   employees e1
+JOIN   employees e2
+JOIN   employees e3
+ON     e1.manager_id=e2.employee_id
+AND    e2.manager_id=e3.employee_id
+where  e3.manager_id=1
+AND    e1.employee_id!=1;
 ```
 
 <!-- tabs:end -->

solution/1200-1299/1270.All People Report to the Given Manager/Solution.sql

@@ -0,0 +1,9 @@
+# Write your MySQL query statement below
+SELECT e1.employee_id
+FROM   employees e1
+JOIN   employees e2
+JOIN   employees e3
+ON     e1.manager_id=e2.employee_id
+AND    e2.manager_id=e3.employee_id
+where  e3.manager_id=1
+AND    e1.employee_id!=1;