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feat: add solutions to lc/lcof2 problems (doocs#629)
* feat: add solutions to lc/lcof2 problems * feat: add solutions to lc/lcof2 problems * feat: update README.md
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‎lcof2/剑指 Offer II 002. 二进制加法/README.md

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@@ -139,6 +139,34 @@ func addBinary(a string, b string) string {
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}
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```
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### **C++**
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```cpp
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class Solution {
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public:
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string addBinary(string a, string b) {
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string res;
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int carry = 0;
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int i = a.size() - 1;
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int j = b.size() - 1;
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while (i >= 0 || j >= 0) {
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int digitA = i >= 0 ? a.at(i--) - '0' : 0;
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int digitB = j >= 0 ? b.at(j--) - '0' : 0;
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int sum = digitA + digitB + carry;
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carry = sum >= 2 ? 1 : 0;
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sum = sum >= 2 ? sum - 2 : sum;
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res += to_string(sum);
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}
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if (carry == 1) res.push_back('1');
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reverse(res.begin(), res.end());
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return res;
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}
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};
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```
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### **...**
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```

‎lcof2/剑指 Offer II 002. 二进制加法/Solution.cpp

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class Solution {
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public:
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string addBinary(string a, string b) {
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string res;
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int carry = 0;
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int i = a.size() - 1;
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int j = b.size() - 1;
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while (i >= 0 || j >= 0) {
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int digitA = i >= 0 ? a.at(i--) - '0' : 0;
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int digitB = j >= 0 ? b.at(j--) - '0' : 0;
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int sum = digitA + digitB + carry;
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carry = sum >= 2 ? 1 : 0;
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sum = sum >= 2 ? sum - 2 : sum;
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res += to_string(sum);
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}
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if (carry == 1) res.push_back('1');
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reverse(res.begin(), res.end());
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return res;
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}
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};

‎lcof2/剑指 Offer II 003. 前 n 个数字二进制中 1 的个数/README.md

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@@ -103,6 +103,22 @@ func countBits(n int) []int {
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}
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```
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### **C++**
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```cpp
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class Solution {
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public:
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vector<int> countBits(int n) {
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vector<int> res(n + 1);
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for (int i = 1; i <= n; i++) {
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res[i] = res[i & (i - 1)] + 1;
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}
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return res;
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}
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};
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```
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### **...**
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```

‎lcof2/剑指 Offer II 003. 前 n 个数字二进制中 1 的个数/Solution.cpp

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class Solution {
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public:
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vector<int> countBits(int n) {
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vector<int> res(n + 1);
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for (int i = 1; i <= n; i++) {
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res[i] = res[i & (i - 1)] + 1;
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}
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return res;
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}
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};

‎lcof2/剑指 Offer II 005. 单词长度的最大乘积/README.md

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@@ -130,6 +130,40 @@ func max(a, b int) int {
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}
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```
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### **C++**
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```cpp
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class Solution {
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public:
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int maxProduct(vector<string>& words) {
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vector<vector<bool>> hash(words.size(), vector<bool>(26, false));
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for (int i = 0; i < words.size(); i++)
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for (char c: words[i])
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hash[i][c - 'a'] = true;
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int res = 0;
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for (int i = 0; i < words.size(); i++) {
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for (int j = i + 1; j < words.size(); j++) {
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int k = 0;
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for (; k < 26; k++) {
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if (hash[i][k] && hash[j][k])
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break;
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}
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if (k == 26) {
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int prod = words[i].size() * words[j].size();
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res = max(res, prod);
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}
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}
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}
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return res;
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}
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};
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```
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### **...**
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```

‎lcof2/剑指 Offer II 005. 单词长度的最大乘积/Solution.cpp

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class Solution {
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public:
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int maxProduct(vector<string>& words) {
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vector<vector<bool>> hash(words.size(), vector<bool>(26, false));
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for (int i = 0; i < words.size(); i++)
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for (char c: words[i])
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hash[i][c - 'a'] = true;
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int res = 0;
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for (int i = 0; i < words.size(); i++) {
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for (int j = i + 1; j < words.size(); j++) {
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int k = 0;
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for (; k < 26; k++) {
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if (hash[i][k] && hash[j][k])
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break;
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}
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if (k == 26) {
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int prod = words[i].size() * words[j].size();
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res = max(res, prod);
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}
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}
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}
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return res;
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}
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};

‎lcof2/剑指 Offer II 007. 数组中和为 0 的三个数/README.md

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@@ -154,6 +154,42 @@ func threeSum(nums []int) [][]int {
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}
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```
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### **C++**
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```cpp
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class Solution {
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public:
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vector<vector<int>> threeSum(vector<int>& nums) {
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vector<vector<int>> res;
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sort(nums.begin(), nums.end());
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for (int k = 0; k < nums.size(); k++) {
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int i = k + 1;
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int j = nums.size() - 1;
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if (k > 0 && nums[k] == nums[k - 1]) continue;
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while(i < j) {
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if (nums[i] + nums[j] + nums[k] == 0) {
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res.push_back(vector<int>{nums[k], nums[i], nums[j]});
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i++;
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j--;
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while(i < j && nums[i] == nums[i - 1]) i++;
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while(i < j && nums[j] == nums[j + 1]) j--;
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} else if (nums[i] + nums[j] + nums[k] < 0) {
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i++;
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} else {
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j--;
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}
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}
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}
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return res;
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}
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};
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```
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### **...**
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```

‎lcof2/剑指 Offer II 007. 数组中和为 0 的三个数/Solution.cpp

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class Solution {
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public:
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vector<vector<int>> threeSum(vector<int>& nums) {
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vector<vector<int>> res;
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sort(nums.begin(), nums.end());
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for (int k = 0; k < nums.size(); k++) {
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int i = k + 1;
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int j = nums.size() - 1;
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if (k > 0 && nums[k] == nums[k - 1]) continue;
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while(i < j) {
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if (nums[i] + nums[j] + nums[k] == 0) {
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res.push_back(vector<int>{nums[k], nums[i], nums[j]});
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i++;
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j--;
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while(i < j && nums[i] == nums[i - 1]) i++;
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while(i < j && nums[j] == nums[j + 1]) j--;
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} else if (nums[i] + nums[j] + nums[k] < 0) {
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i++;
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} else {
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j--;
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}
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}
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}
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return res;
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}
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};

‎solution/0000-0099/0067.Add Binary/README.md

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@@ -70,6 +70,36 @@ class Solution {
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}
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```
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### **C++**
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```cpp
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class Solution {
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public:
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string addBinary(string a, string b) {
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string res;
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int carry = 0;
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int i = a.size() - 1;
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int j = b.size() - 1;
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while (i >= 0 || j >= 0) {
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int digitA = i >= 0 ? a.at(i--) - '0' : 0;
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int digitB = j >= 0 ? b.at(j--) - '0' : 0;
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int sum = digitA + digitB + carry;
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carry = sum >= 2 ? 1 : 0;
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sum = sum >= 2 ? sum - 2 : sum;
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res += to_string(sum);
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}
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if (carry == 1) res.push_back('1');
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reverse(res.begin(), res.end());
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return res;
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}
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};
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```
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### **C#**
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```cs

‎solution/0000-0099/0067.Add Binary/README_EN.md

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@@ -55,6 +55,35 @@ class Solution {
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}
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```
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### **C++**
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```cpp
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class Solution {
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public:
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string addBinary(string a, string b) {
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string res;
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int carry = 0;
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int i = a.size() - 1;
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int j = b.size() - 1;
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while (i >= 0 || j >= 0) {
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int digitA = i >= 0 ? a.at(i--) - '0' : 0;
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int digitB = j >= 0 ? b.at(j--) - '0' : 0;
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int sum = digitA + digitB + carry;
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carry = sum >= 2 ? 1 : 0;
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sum = sum >= 2 ? sum - 2 : sum;
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res += to_string(sum);
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}
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if (carry == 1) res.push_back('1');
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reverse(res.begin(), res.end());
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return res;
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}
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};
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```
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### **C#**
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```cs

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