feat: add solutions to lc problem: No.0312. Burst Balloons

Author: yanglbme

solution/0300-0399/0312.Burst Balloons/README.md

@@ -39,27 +39,120 @@ coins =  3*1*5    +   3*5*8   +  1*3*8  + 1*8*1 = 167</pre>
 	<li><code>0 <= nums[i] <= 100</code></li>
 </ul>
 
-
 ## 解法
 
 <!-- 这里可写通用的实现逻辑 -->
 
+区间 DP。
+
+- 状态表示：`dp[i][j]` 表示戳破区间 `(i, j)` 内所有气球获得的最大硬币数。
+- 状态计算：枚举开区间 `(i, j)` 中以气球 k 作为最后戳破的气球。那么 `dp[i][j] = max(dp[i][k] + dp[k][j] + nums[i] * nums[k] * nums[j]), k ∈ [i + 1, j)`。
+
+以区间长度 l 从小到大开始处理每个状态值。
+
 <!-- tabs:start -->
 
 ### **Python3**
 
 <!-- 这里可写当前语言的特殊实现逻辑 -->
 
 ```python
-
+class Solution:
+    def maxCoins(self, nums: List[int]) -> int:
+        nums = [1] + nums + [1]
+        n = len(nums)
+        dp = [[0] * n for _ in range(n)]
+        for l in range(2, n):
+            for i in range(n - l):
+                j = i + l
+                for k in range(i + 1, j):
+                    dp[i][j] = max(dp[i][j], dp[i][k] + dp[k][j] + nums[i] * nums[k] * nums[j])
+        return dp[0][-1]
 ```
 
 ### **Java**
 
 <!-- 这里可写当前语言的特殊实现逻辑 -->
 
 ```java
+class Solution {
+    public int maxCoins(int[] nums) {
+        int[] vals = new int[nums.length + 2];
+        vals[0] = 1;
+        vals[vals.length - 1] = 1;
+        System.arraycopy(nums, 0, vals, 1, nums.length);
+        int n = vals.length;
+        int[][] dp = new int[n][n];
+        for (int l = 2; l < n; ++l) {
+            for (int i = 0; i + l < n; ++i) {
+                int j = i + l;
+                for (int k = i + 1; k < j; ++k) {
+                    dp[i][j] = Math.max(dp[i][j], dp[i][k] + dp[k][j] + vals[i] * vals[k] * vals[j]);
+                }
+            }
+        }
+        return dp[0][n - 1];
+    }
+}
+```
+
+### **C++**
+
+```cpp
+class Solution {
+public:
+    int maxCoins(vector<int>& nums) {
+        nums.insert(nums.begin(), 1);
+        nums.push_back(1);
+        int n = nums.size();
+        vector<vector<int>> dp(n, vector<int>(n));
+        for (int l = 2; l < n; ++l)
+        {
+            for (int i = 0; i + l < n; ++i)
+            {
+                int j = i + l;
+                for (int k = i + 1; k < j; ++k)
+                {
+                    dp[i][j] = max(dp[i][j], dp[i][k] + dp[k][j] + nums[i] * nums[k] * nums[j]);
+                }
+            }
+        }
+        return dp[0][n - 1];
+    }
+};
+```
 
+### **Go**
+
+```go
+func maxCoins(nums []int) int {
+	vals := make([]int, len(nums)+2)
+	for i := 0; i < len(nums); i++ {
+		vals[i+1] = nums[i]
+	}
+	n := len(vals)
+	vals[0], vals[n-1] = 1, 1
+	dp := make([][]int, n)
+	for i := 0; i < n; i++ {
+		dp[i] = make([]int, n)
+	}
+	for l := 2; l < n; l++ {
+		for i := 0; i+l < n; i++ {
+			j := i + l
+			for k := i + 1; k < j; k++ {
+				dp[i][j] = max(dp[i][j], dp[i][k]+dp[k][j]+vals[i]*vals[k]*vals[j])
+			}
+		}
+	}
+	return dp[0][n-1]
+}
+
+func max(a, b int) int {
+	if a > b {
+		return a
+	}
+	return b
+}
 ```
 
 ### **...**

solution/0300-0399/0312.Burst Balloons/README_EN.md

@@ -36,21 +36,107 @@ coins =  3*1*5    +   3*5*8   +  1*3*8  + 1*8*1 = 167</pre>
 	<li><code>0 &lt;= nums[i] &lt;= 100</code></li>
 </ul>
 
-
 ## Solutions
 
 <!-- tabs:start -->
 
 ### **Python3**
 
 ```python
-
+class Solution:
+    def maxCoins(self, nums: List[int]) -> int:
+        nums = [1] + nums + [1]
+        n = len(nums)
+        dp = [[0] * n for _ in range(n)]
+        for l in range(2, n):
+            for i in range(n - l):
+                j = i + l
+                for k in range(i + 1, j):
+                    dp[i][j] = max(dp[i][j], dp[i][k] + dp[k][j] + nums[i] * nums[k] * nums[j])
+        return dp[0][-1]
 ```
 
 ### **Java**
 
 ```java
+class Solution {
+    public int maxCoins(int[] nums) {
+        int[] vals = new int[nums.length + 2];
+        vals[0] = 1;
+        vals[vals.length - 1] = 1;
+        System.arraycopy(nums, 0, vals, 1, nums.length);
+        int n = vals.length;
+        int[][] dp = new int[n][n];
+        for (int l = 2; l < n; ++l) {
+            for (int i = 0; i + l < n; ++i) {
+                int j = i + l;
+                for (int k = i + 1; k < j; ++k) {
+                    dp[i][j] = Math.max(dp[i][j], dp[i][k] + dp[k][j] + vals[i] * vals[k] * vals[j]);
+                }
+            }
+        }
+        return dp[0][n - 1];
+    }
+}
+```
+
+### **C++**
+
+```cpp
+class Solution {
+public:
+    int maxCoins(vector<int>& nums) {
+        nums.insert(nums.begin(), 1);
+        nums.push_back(1);
+        int n = nums.size();
+        vector<vector<int>> dp(n, vector<int>(n));
+        for (int l = 2; l < n; ++l)
+        {
+            for (int i = 0; i + l < n; ++i)
+            {
+                int j = i + l;
+                for (int k = i + 1; k < j; ++k)
+                {
+                    dp[i][j] = max(dp[i][j], dp[i][k] + dp[k][j] + nums[i] * nums[k] * nums[j]);
+                }
+            }
+        }
+        return dp[0][n - 1];
+    }
+};
+```
 
+### **Go**
+
+```go
+func maxCoins(nums []int) int {
+	vals := make([]int, len(nums)+2)
+	for i := 0; i < len(nums); i++ {
+		vals[i+1] = nums[i]
+	}
+	n := len(vals)
+	vals[0], vals[n-1] = 1, 1
+	dp := make([][]int, n)
+	for i := 0; i < n; i++ {
+		dp[i] = make([]int, n)
+	}
+	for l := 2; l < n; l++ {
+		for i := 0; i+l < n; i++ {
+			j := i + l
+			for k := i + 1; k < j; k++ {
+				dp[i][j] = max(dp[i][j], dp[i][k]+dp[k][j]+vals[i]*vals[k]*vals[j])
+			}
+		}
+	}
+	return dp[0][n-1]
+}
+
+func max(a, b int) int {
+	if a > b {
+		return a
+	}
+	return b
+}
 ```
 
 ### **...**

solution/0300-0399/0312.Burst Balloons/Solution.cpp

@@ -0,0 +1,21 @@
+class Solution {
+public:
+    int maxCoins(vector<int>& nums) {
+        nums.insert(nums.begin(), 1);
+        nums.push_back(1);
+        int n = nums.size();
+        vector<vector<int>> dp(n, vector<int>(n));
+        for (int l = 2; l < n; ++l)
+        {
+            for (int i = 0; i + l < n; ++i)
+            {
+                int j = i + l;
+                for (int k = i + 1; k < j; ++k)
+                {
+                    dp[i][j] = max(dp[i][j], dp[i][k] + dp[k][j] + nums[i] * nums[k] * nums[j]);
+                }
+            }
+        }
+        return dp[0][n - 1];
+    }
+};

solution/0300-0399/0312.Burst Balloons/Solution.go

@@ -0,0 +1,28 @@
+func maxCoins(nums []int) int {
+	vals := make([]int, len(nums)+2)
+	for i := 0; i < len(nums); i++ {
+		vals[i+1] = nums[i]
+	}
+	n := len(vals)
+	vals[0], vals[n-1] = 1, 1
+	dp := make([][]int, n)
+	for i := 0; i < n; i++ {
+		dp[i] = make([]int, n)
+	}
+	for l := 2; l < n; l++ {
+		for i := 0; i+l < n; i++ {
+			j := i + l
+			for k := i + 1; k < j; k++ {
+				dp[i][j] = max(dp[i][j], dp[i][k]+dp[k][j]+vals[i]*vals[k]*vals[j])
+			}
+		}
+	}
+	return dp[0][n-1]
+}
+
+func max(a, b int) int {
+	if a > b {
+		return a
+	}
+	return b
+}

solution/0300-0399/0312.Burst Balloons/Solution.java

@@ -1,38 +1,19 @@
 class Solution {
-    
     public int maxCoins(int[] nums) {
-        if (nums == null || nums.length == 0) {
-            return 0;
-        }
-        int n = nums.length;
-        int[][] f = new int[n + 2][n + 2];
-        for (int i= 0; i < n + 2; ++i) {
-            for (int j = 0; j < n + 2; ++j) {
-                f[i][j] = -1;
+        int[] vals = new int[nums.length + 2];
+        vals[0] = 1;
+        vals[vals.length - 1] = 1;
+        System.arraycopy(nums, 0, vals, 1, nums.length);
+        int n = vals.length;
+        int[][] dp = new int[n][n];
+        for (int l = 2; l < n; ++l) {
+            for (int i = 0; i + l < n; ++i) {
+                int j = i + l;
+                for (int k = i + 1; k < j; ++k) {
+                    dp[i][j] = Math.max(dp[i][j], dp[i][k] + dp[k][j] + vals[i] * vals[k] * vals[j]);
+                }
             }
         }
-        int[] bak = new int[n + 2];
-        bak[0] = bak[n + 1] = 1;
-        for (int i = 1; i < n + 1; ++i) {
-            bak[i] = nums[i - 1];
-        }
-        return dp(bak, f, 0, n + 1);
-    }
-    
-    private int dp(int[] nums, int[][] f, int x, int y) {
-        if (f[x][y] != -1) {
-            return f[x][y];
-        }
-        
-        f[x][y] = 0;
-        
-        //枚举最后一个戳破的气球的位置
-        for (int i = x + 1; i < y; ++i) {
-            f[x][y] = Math.max(f[x][y], nums[i] * nums[x] * nums[y] + dp(nums,f,  x, i) + dp(nums, f, i, y));
-        }
-        return f[x][y];
-        
+        return dp[0][n - 1];
     }
-    
-    
 }

solution/0300-0399/0312.Burst Balloons/Solution.py

@@ -0,0 +1,11 @@
+class Solution:
+    def maxCoins(self, nums: List[int]) -> int:
+        nums = [1] + nums + [1]
+        n = len(nums)
+        dp = [[0] * n for _ in range(n)]
+        for l in range(2, n):
+            for i in range(n - l):
+                j = i + l
+                for k in range(i + 1, j):
+                    dp[i][j] = max(dp[i][j], dp[i][k] + dp[k][j] + nums[i] * nums[k] * nums[j])
+        return dp[0][-1]