feat: add solutions to lc problem: No.1549

No.1549.The Most Recent Orders for Each Product

Author: yanglbme

solution/1500-1599/1537.Get the Maximum Score/README.md

@@ -72,8 +72,6 @@
 
 <!-- 这里可写通用的实现逻辑 -->
 
-
-
 <!-- tabs:start -->
 
 ### **Python3**

solution/1500-1599/1549.The Most Recent Orders for Each Product/README.md

@@ -124,7 +124,29 @@ hard disk 没有被下单, 我们不把它包含在结果表中.</pre>
 ### **SQL**
 
 ```sql
-
+# Write your MySQL query statement below
+select
+    product_name,
+    o.product_id,
+    o.order_id,
+    o.order_date
+from
+    Orders o
+    join Products p on o.product_id = p.product_id
+where
+    (o.product_id, order_date) in (
+        select
+            product_id,
+            max(order_date) order_date
+        from
+            Orders
+        group by
+            product_id
+    )
+order by
+    product_name,
+    o.product_id,
+    o.order_id
 ```
 
 <!-- tabs:end -->

solution/1500-1599/1549.The Most Recent Orders for Each Product/README_EN.md

@@ -120,7 +120,29 @@ The hard disk was never ordered and we do not include it in the result table.
 ### **SQL**
 
 ```sql
-
+# Write your MySQL query statement below
+select
+    product_name,
+    o.product_id,
+    o.order_id,
+    o.order_date
+from
+    Orders o
+    join Products p on o.product_id = p.product_id
+where
+    (o.product_id, order_date) in (
+        select
+            product_id,
+            max(order_date) order_date
+        from
+            Orders
+        group by
+            product_id
+    )
+order by
+    product_name,
+    o.product_id,
+    o.order_id
 ```
 
 <!-- tabs:end -->

solution/1500-1599/1549.The Most Recent Orders for Each Product/Solution.sql

@@ -0,0 +1,23 @@
+# Write your MySQL query statement below
+select
+    product_name,
+    o.product_id,
+    o.order_id,
+    o.order_date
+from
+    Orders o
+    join Products p on o.product_id = p.product_id
+where
+    (o.product_id, order_date) in (
+        select
+            product_id,
+            max(order_date) order_date
+        from
+            Orders
+        group by
+            product_id
+    )
+order by
+    product_name,
+    o.product_id,
+    o.order_id