feat: add typescript solution to lc problem: No.2437

No.2437.Number of Valid Clock Times

Author: zhaocchen

solution/2400-2499/2437.Number of Valid Clock Times/README.md

@@ -153,7 +153,29 @@ func countTime(time string) int {
 ### **TypeScript**
 
 ```ts
+function countTime(time: string): number {
+    let [hh, mm] = time.split(':');
+    return count(hh, 24) * count(mm, 60);
+};
 
+function count(str: string, limit: number): number {
+    let [a, b] = str.split('').map(d => Number(d));
+    let ans = 0;
+    if (isNaN(a) && isNaN(b)) return limit;
+    if (isNaN(a)) {
+        for (let i = 0; i <= 9; i++) {
+            if (i * 10 + b < limit) ans++;
+        }
+        return ans;
+    }
+    if (isNaN(b)) {
+        for (let i = 0; i <= 9; i++) {
+            if (a * 10 + i < limit) ans++;
+        }
+        return ans;
+    }
+    return 1;
+}
 ```
 
 ### **...**

solution/2400-2499/2437.Number of Valid Clock Times/README_EN.md

@@ -140,7 +140,29 @@ func countTime(time string) int {
 ### **TypeScript**
 
 ```ts
+function countTime(time: string): number {
+    let [hh, mm] = time.split(':');
+    return count(hh, 24) * count(mm, 60);
+};
 
+function count(str: string, limit: number): number {
+    let [a, b] = str.split('').map(d => Number(d));
+    let ans = 0;
+    if (isNaN(a) && isNaN(b)) return limit;
+    if (isNaN(a)) {
+        for (let i = 0; i <= 9; i++) {
+            if (i * 10 + b < limit) ans++;
+        }
+        return ans;
+    }
+    if (isNaN(b)) {
+        for (let i = 0; i <= 9; i++) {
+            if (a * 10 + i < limit) ans++;
+        }
+        return ans;
+    }
+    return 1;
+}
 ```
 
 ### **...**

solution/2400-2499/2437.Number of Valid Clock Times/Solution.ts

@@ -0,0 +1,23 @@
+function countTime(time: string): number {
+    let [hh, mm] = time.split(':');
+    return count(hh, 24) * count(mm, 60);
+};
+
+function count(str: string, limit: number): number {
+    let [a, b] = str.split('').map(d => Number(d));
+    let ans = 0;
+    if (isNaN(a) && isNaN(b)) return limit;
+    if (isNaN(a)) {
+        for (let i = 0; i <= 9; i++) {
+            if (i * 10 + b < limit) ans++;
+        }
+        return ans;
+    }
+    if (isNaN(b)) {
+        for (let i = 0; i <= 9; i++) {
+            if (a * 10 + i < limit) ans++;
+        }
+        return ans;
+    }
+    return 1;
+}