feat: add sql solution to lc problem: No.1225

No.1225.Report Contiguous Dates

Author: yanglbme

solution/1200-1299/1225.Report Contiguous Dates/README.md

@@ -85,7 +85,50 @@ Result table:
 ### **SQL**
 
 ```sql
-
+# Write your MySQL query statement below
+select
+    state as period_state,
+    min(dt) as start_date,
+    max(dt) as end_date
+from
+    (
+        select
+            *,
+            subdate(
+                dt,
+                rank() over(
+                    partition by state
+                    order by
+                        dt
+                )
+            ) as dif
+        from
+            (
+                select
+                    'failed' as state,
+                    fail_date as dt
+                from
+                    failed
+                where
+                    fail_date between '2019-01-01'
+                    and '2019-12-31'
+                union
+                all
+                select
+                    'succeeded' as state,
+                    success_date as dt
+                from
+                    succeeded
+                where
+                    success_date between '2019-01-01'
+                    and '2019-12-31'
+            ) t1
+    ) t2
+group by
+    state,
+    dif
+order by
+    dt
 ```
 
 <!-- tabs:end -->

solution/1200-1299/1225.Report Contiguous Dates/README_EN.md

@@ -89,7 +89,50 @@ From 2019-01-06 to 2019-01-06 all tasks succeeded and the system state was &quot
 ### **SQL**
 
 ```sql
-
+# Write your MySQL query statement below
+select
+    state as period_state,
+    min(dt) as start_date,
+    max(dt) as end_date
+from
+    (
+        select
+            *,
+            subdate(
+                dt,
+                rank() over(
+                    partition by state
+                    order by
+                        dt
+                )
+            ) as dif
+        from
+            (
+                select
+                    'failed' as state,
+                    fail_date as dt
+                from
+                    failed
+                where
+                    fail_date between '2019-01-01'
+                    and '2019-12-31'
+                union
+                all
+                select
+                    'succeeded' as state,
+                    success_date as dt
+                from
+                    succeeded
+                where
+                    success_date between '2019-01-01'
+                    and '2019-12-31'
+            ) t1
+    ) t2
+group by
+    state,
+    dif
+order by
+    dt
 ```
 
 <!-- tabs:end -->

solution/1200-1299/1225.Report Contiguous Dates/Solution.sql

@@ -0,0 +1,44 @@
+# Write your MySQL query statement below
+select
+    state as period_state,
+    min(dt) as start_date,
+    max(dt) as end_date
+from
+    (
+        select
+            *,
+            subdate(
+                dt,
+                rank() over(
+                    partition by state
+                    order by
+                        dt
+                )
+            ) as dif
+        from
+            (
+                select
+                    'failed' as state,
+                    fail_date as dt
+                from
+                    failed
+                where
+                    fail_date between '2019-01-01'
+                    and '2019-12-31'
+                union
+                all
+                select
+                    'succeeded' as state,
+                    success_date as dt
+                from
+                    succeeded
+                where
+                    success_date between '2019-01-01'
+                    and '2019-12-31'
+            ) t1
+    ) t2
+group by
+    state,
+    dif
+order by
+    dt