feat: add sql solution to lc problems: No.1158,1393,1407

- No.1158.Market Analysis I
- No.1393.Capital GainLoss
- No.1407.Top Travellers

Author: YangFong

solution/1100-1199/1158.Market Analysis I/README.md

@@ -114,7 +114,29 @@ Items 表:
 ### **SQL**
 
 ```sql
+SELECT user_id AS buyer_id,
+    join_date,
+    COUNT(order_id) AS orders_in_2019
+FROM users AS u
+    LEFT JOIN orders AS o ON u.user_id = o.buyer_id
+    AND YEAR(order_date) = 2019
+GROUP BY user_id;
+```
 
+```sql
+SELECT
+    user_id AS buyer_id,
+    join_date,
+    (
+        SELECT
+            COUNT(*)
+        FROM
+            orders AS o
+        WHERE
+            u.user_id = o.buyer_id AND YEAR(order_date) = 2019
+    ) AS orders_in_2019
+FROM
+    users AS u;
 ```
 
 <!-- tabs:end -->

solution/1100-1199/1158.Market Analysis I/README_EN.md

@@ -111,7 +111,29 @@ Items table:
 ### **SQL**
 
 ```sql
+SELECT user_id AS buyer_id,
+    join_date,
+    COUNT(order_id) AS orders_in_2019
+FROM users AS u
+    LEFT JOIN orders AS o ON u.user_id = o.buyer_id
+    AND YEAR(order_date) = 2019
+GROUP BY user_id;
+```
 
+```sql
+SELECT
+    user_id AS buyer_id,
+    join_date,
+    (
+        SELECT
+            COUNT(*)
+        FROM
+            orders AS o
+        WHERE
+            u.user_id = o.buyer_id AND YEAR(order_date) = 2019
+    ) AS orders_in_2019
+FROM
+    users AS u;
 ```
 
 <!-- tabs:end -->

solution/1100-1199/1158.Market Analysis I/Solution.sql

@@ -0,0 +1,7 @@
+SELECT user_id AS buyer_id,
+    join_date,
+    COUNT(order_id) AS orders_in_2019
+FROM users AS u
+    LEFT JOIN orders AS o ON u.user_id = o.buyer_id
+    AND YEAR(order_date) = 2019
+GROUP BY user_id;

solution/1300-1399/1393.Capital GainLoss/README.md

@@ -72,16 +72,15 @@ Corona Masks 股票在第1天以10美元的价格买入，在第3天以1010美
 ### **SQL**
 
 ```sql
-# Write your MySQL query statement below
-SELECT
-    stock_name,
-    sum(
-        CASE WHEN operation = 'Buy' THEN -price ELSE price END
+SELECT stock_name,
+    SUM(
+        CASE
+            WHEN operation = 'Buy' THEN - price
+            ELSE price
+        END
     ) AS capital_gain_loss
-FROM
-    Stocks
-GROUP BY
-    stock_name;
+FROM Stocks
+GROUP BY stock_name;
 ```
 
 <!-- tabs:end -->

solution/1300-1399/1393.Capital GainLoss/README_EN.md

@@ -72,16 +72,15 @@ Corona Masks stock was bought at day 1 for 10$ and was sold at day 3 for 1010$.
 ### **SQL**
 
 ```sql
-# Write your MySQL query statement below
-SELECT
-    stock_name,
-    sum(
-        CASE WHEN operation = 'Buy' THEN -price ELSE price END
+SELECT stock_name,
+    SUM(
+        CASE
+            WHEN operation = 'Buy' THEN - price
+            ELSE price
+        END
     ) AS capital_gain_loss
-FROM
-    Stocks
-GROUP BY
-    stock_name;
+FROM Stocks
+GROUP BY stock_name;
 ```
 
 <!-- tabs:end -->

solution/1300-1399/1393.Capital GainLoss/Solution.sql

@@ -1,10 +1,9 @@
-# Write your MySQL query statement below
-SELECT
-    stock_name,
-    sum(
-        CASE WHEN operation = 'Buy' THEN -price ELSE price END
+SELECT stock_name,
+    SUM(
+        CASE
+            WHEN operation = 'Buy' THEN - price
+            ELSE price
+        END
     ) AS capital_gain_loss
-FROM
-    Stocks
-GROUP BY
-    stock_name;
+FROM Stocks
+GROUP BY stock_name;

solution/1400-1499/1407.Top Travellers/README.md

@@ -97,7 +97,15 @@ Donald 没有任何行程, 他的旅行距离为 0。
 ### **SQL**
 
 ```sql
-
+SELECT name,
+    COALESCE(SUM(distance), 0) AS travelled_distance
+FROM Users AS u
+    LEFT JOIN Rides AS r ON u.id = r.user_id
+GROUP BY
+    name
+ORDER BY
+    travelled_distance DESC,
+    name;
 ```
 
 <!-- tabs:end -->

solution/1400-1499/1407.Top Travellers/README_EN.md

@@ -97,7 +97,15 @@ Donald did not have any rides, the distance traveled by him is 0.
 ### **SQL**
 
 ```sql
-
+SELECT name,
+    COALESCE(SUM(distance), 0) AS travelled_distance
+FROM Users AS u
+    LEFT JOIN Rides AS r ON u.id = r.user_id
+GROUP BY
+    name
+ORDER BY
+    travelled_distance DESC,
+    name;
 ```
 
 <!-- tabs:end -->

solution/1400-1499/1407.Top Travellers/Solution.sql

@@ -0,0 +1,9 @@
+SELECT name,
+    COALESCE(SUM(distance), 0) AS travelled_distance
+FROM Users AS u
+    LEFT JOIN Rides AS r ON u.id = r.user_id
+GROUP BY
+    name
+ORDER BY
+    travelled_distance DESC,
+    name;